# VPHASE Voltage optermisation

The Basics Saru Systems can fit a device to your incomming supply that will reduce your Electricity Bill. It will Stop consumer goods wasting electricity by running too hot. The instalation will extend the life of Fridges and Freezers and make them use less electricity. light bulbs last longer and become more efficient. Look to save in excess of £80 per year You reduce your carbon foot print with out spending vast ammonuts of money.

How it Works

** ****Ohm’s Law**

Everybody knows that P = I x V

(that is, Power = Current x Voltage

or Watts = Amps x Volts)

So if you reduce voltage, current will rise and the power will remain constant.

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| | __ ____The answer:__
**The misconception about P = I x V is based on the assumption that electrical loads have constant power: That is, a 1kW motor will use 1kW, and if either current or voltage changes, the other will change to compensate in order to maintain that 1kW of power. That is not what this formula means. In fact, all it ****is saying is that the power being drawn is the product of current and voltage**.
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| | **The principle of energy saving through voltage optimisation is that the nameplate power of a device (say, 1kW for a motor, or 60W for a light bulb) will be delivered at any voltage within an operating range, which is 216 - 254V in the UK. But above a certain optimum voltage, additional energy will be used for no improvement in performance.**
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| | **So a motor that is designed to work anywhere in Europe will have an optimum operating point at 220V. Above this voltage, for example at the UK supply average of 242V, the motor will deliver its rated power (i.e. torque), but will use additional energy as heat and vibration as the core is driven into saturation and iron and copper losses increase. **
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| | **So by efficiently removing the difference between the supply voltage ****and optimum voltage, the voltage optimisation brings all equipment to its most ****efficient operating point, without affecting its performance. ****All that we assume in the above analysis is that resistance is constant. **
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| **Ohm’sLaw also knows that V = I x R, so it follows that I = V / R and as P = I x V from before, it follows that P = V2/ R, by substitution. **
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| | **So according to this, if you reduce voltage, power will also reduce as the square of voltage. This is what happens in real life with most electrical**
**equipment, and is the reason that the voltage optimisation saves energy. It means that an 8% reduction in a 240V supply voltage on a 20Ω ****load will cause the power to drop from 2880W to 2420W, which is a 16% saving.**
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